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The observational sample consisted of 30 bottles of soda containing ounces of product. The mean, median, and standard deviations were determined to better comprehend the required quantity of ounces as advertised by the company.
Mean Solution
14.23 + 14.32 + 14.98 + 15 + 15.11 + 15.21 + 15.42 + 15.47 + 15.65 + 15.74 + 15.77 + 15.8 + 15.82 + 15.87 + 15.98 + 16 + 16.02 + 16.05 + 16.21 + 16.21 + 16.23 + 16.25 + 16.31 + 16.32 + 16.34 + 16.46 + 16.47 + 16.51 + 16.91 + 16.96
475.62
Therefore, the sample mean is 15.854 ounces per soda bottle.
Median
The median is also a measure of central tendency which provides information about the middle observation in the sample. Since the number of observations is even, the middle number will be between the 15th and the 16th observation.
Solution
Median
Standard Deviation
Bottle number
x
Bottle number
x
14.23
-1.624
2.637376
16
0.146
0.021316
14.32
-1.534
2.353156
16.02
0.166
0.027556
14.98
-0.874
0.763876
16.05
0.196
0.038416
15
-0.854
0.729316
16.21
0.356
0.126736
15.11
-0.744
0.553536
16.21
0.356
0.126736
15.21
-0.644
0.414736
16.23
0.376
0.141376
15.42
-0.434
0.188356
16.25
0.396
0.156816
15.47
-0.384
0.147456
16.31
0.456
0.207936
15.65
-0.204
0.041616
16.32
0.466
0.217156
15.74
-0.114
0.012996
16.34
0.486
0.236196
15.77
-0.084
0.007056
16.46
0.606
0.367236
15.8
-0.054
0.002916
16.47
0.616
0.379456
15.82
-0.034
0.001156
16.51
0.656
0.430336
15.87
0.016
0.000256
16.91
1.056
1.115136
15.98
0.126
0.015876
16.96
1.106
1.223236
Solution
Question 2
The 95% confidence interval implies that the level of significance (alpha) is 5%. The t-test was used to calculate the 95% confidence interval at 5% level of significance and (n-1) degrees of freedom. Therefore, the confidence interval is given by;
Student t-test
= 15.854
s = 0.6614
n = 30
The lower limit is given by 15.6071 while the upper limit is 16.109. This represents the range in which the amount of ounces in the soda bottles would lie in the case of repeated sampling.
Question 3
Hypotheses:
Ho: On average the bottles contain 16 ounces of products
H1: On average the bottles contain less than 16 ounces of product.
We proceed to test the validity of the hypotheses using the t-test at 5% level of significance and (n-1) degrees of freedom as shown below.
.Solution
The t calculated value =
We compare the t calculated value with the t critical value obtained from the statistical tables. The t tabulated value is given by;
T tabulated =
In this case, the tabulated t value is smaller than the t calculated value implying that we fail to reject the null hypothesis. Therefore, from the statistical analysis above, the customers’ claim of the bottles containing less than 16ounces of product is not valid.
Question 4
The conclusion of rejecting the customers’ claim is supported statistically at the 95% confidence interval. The upper and the lower bounds provide a narrow range over which the mean number of ounces should lie. In this regard, it is evident that some of the bottles will have number of ounces falling outside the range representing defective figure. The existence of the defectives is an indication of poor quality product produced by the company due to various reasons such as the use of inefficient machineries. To avoid complaints from the customers, the company should check for defectives in the sodas produced.
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