Binomial Distribution

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N represents the total number of trials. The number I’ve chosen to work with is 7 X the projected number of successes. Because the number of successes can never be larger than the number of tries in any condition, x must be less than N, which in our instance is 7. As a result, we can use 5 as our x.

P denotes the trial’s success probability. Considering the question, we must keep P = 0.6.

As a result, for N=7, x=5, and p=0.6, the probability is 0.261.

Normal Distribution (Part 2)

Question: select your own values of z1 and z2, then use the Appendix Table for the Standard Normal

Our value of choice for z1 and z2 are: z1 = -2.47

z2 =-1.98

Distribution to find:

1) P (z < z1)

Replacing z1 in the equation with -2.47 which is the value of choice for z2

P (z < -2.47)

Finding the probability from the table we get the solution to be

P (z < -2.47) = 0.00676

= 0.00676

2) P (z > z1)

Replacing z1 in the equation with -2.47 which is the value of choice for z1

P (z > -2.47)

Finding the probability from the table we get the solution to be

P (z > -2.47) = 1 - P (z > -2.47)

= 1- 0.00676

= 0.9932

3) P (z < z2)

Replacing z2 in the equation with -1.98 which is the value of choice for z2

P (z < -1.98)

Finding the probability from the table we get the solution to be

P (z < -1.98) = 0.02385

= 0.02385

4) P (z > z2)

Replacing z2 in this equation with -1.98 which is the value of choice for z2

P (z > -1.98)

Finding the probability from the table we get the solution to be

P (z > -1.98) = 1 - P (z < -1.98)

1 - 0.02385 = 0.9762

= 0.9762

5) P (z1 < z < z2)

Replacing for both z1 and z2 in the equation with z1 = -2.47 and z2 = 1.98 representing the values we choose to work with. The equation P (z1 < z < z2) therefore can be written as:

P (-2.47 < z < -1.98)

Which can be broken and written in a simpler way as

P (z < -1.98) - P (z < -2.47)

Recall that from the above solutions P (z < -1.98) = 0.02385 and P (z < -2.47) = 0.00676.

Therefore, the solution is:

P (z < -1.98) - P (z < -2.47)

= 0.02385 - 0.00676

= 0.0171

May 24, 2023
Category:

Science Life

Subcategory:

Math Myself

Subject area:

Statistics Calculus Values

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359

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